請教數學題

[Somemore]

高手幫幫忙!

[Yu0229]

1. When X=0, y=4. 4=m*1, m=4
   Log8 y= log8 (4n^x) = log8 4 + x log8 n = log 8 (8^(2/3)) + x log8 n = 2/3 + x log8 n
2. graph應該係一個linear嘅，因為0<n<1（當x tends to infinity, y tends to 0），所以log8 n係負數，應該係一條直線slope係負數，向下，穿過(0, 2/3)呢個point

[Somemore]

多謝幫忙!

[CPS]

高手果然在